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Fathookup date

Fathookup date-5

The 's' on the end of 'days', 'years' or other measurements can be left off if you want.

The easiest and most common calculations are based on seconds, minutes, hours and days.In the list above you can see that '3 days ago' is equivalent to '-3 days'.Also 'yesterday' is the same as '-1 days' or '1 day ago'.I would also like it to ignore January & July (meetings do not occur those months) and display the February/August meeting dates instead. Obviously you will need a function for this and not just a single strotime command. I have to pad the results by 1 to get actual calendar day of year..to calcutate the day of the future year.what is the main logic behind this calculation and how does it flow in that method as if the day i want to calcute is and today is so what will be the day on .. I have the code: $t Unix Time= strtotime('second sunday may 2011'); echo $s GMTMy Sql String = gmdate("Y-m-d H:i:s", $t Unix Time); The real answer should be: 2011-05-08 The program is giving: 2011-05-15 what I am doing bad? According to PHP, 1 month after 31 January 2011 will be 31 February. To avoid this you need to calculate the offset from the start of the current month.This should get you started: $lastday = date('Y-m-d', strtotime("last day of last month")); $thismeeting = date('Y-m-d', strtotime("$lastday second Monday")); $lastday = date('Y-m-d', strtotime("last day of this month")); $nextmeeting = date('Y-m-d', strtotime("$lastday second Monday")); You can replace "last month" with "2013-08" if you want to loop through the year. I am trying to create a form that when submitted until 0600 the next day still returns the previous day's date. The officer starts his shift on feb 02 @ 1800 and works until 0600 on Feb 03.

Everything he submits all night should reflect the correct time but default to the starting date (Feb 02).

You may notice also that this only occurs when you're calculating from the current day and not in the previous examples (unless today is Saturday). The following examples show the syntax you can use for this: I am trying to create a formula that will provide the sabbatical date every six years from hire date.

Whenever you do calculations based on days you should test as many possibilities as possible: Does it work today? For example, if an employee's hire date was 9/30/1993, what would the formula be to indicate that another sabbatical is due as of 9/30/2017?

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